Home
Class 11
CHEMISTRY
A bottle of dry ammonia and a bottle of ...

A bottle of dry ammonia and a bottle of dry hydrogen chloride connected through a long tube are opened simultaneously at both ends. The white ammonium chloride ring first formed will be

A

At the centre of the tube

B

Near the hydrogen chloride bottle

C

Near the ammonia bottle

D

Throughout the length of the tube

Text Solution

Verified by Experts

The correct Answer is:
B
`NH_4Cl` ring will first form near the HCl bottle because rate of diffusion of `NH_3` is more than that of HCl (because ) `M_(NH_3) : M_(HCl) = 17:36.5)` So `NH_3` will reach first to the HCl bottle & will react there with HCl to form `NH_4Cl` ring.
Promotional Banner

Similar Questions

Explore conceptually related problems

A bottle of dry NH_(3) and another bottle of dry HCl connected through a long tube are opened simultaneously at both ends of the tube. The white ring (NH_(4)Cl) first formed will be

In the following diagram,container of NH_(3) gas and container of HCl gas, connected through a long tube, are opened simultaneously at both ends, the white NH_(4) Cl ring first formed will be at Q point. If OP = 40 cm , then find OQ -

If one mole of ammonia and one mole of hydrogen chloride are mixed in a closed container to form ammonium chloride vapor, then

Through the two ends of a glass tube of length 200cm hydrogen chloride gas and ammonia are allowed to enter At what distance ammonium chloride will first appear ? .