vt_0_newFlow
vt_0_newFlow
A
150 K
B
600K
C
900K
D
1200K
Text Solution
Verified by Experts
The correct Answer is:
D
`(u_(SO_2))/(u_(He)) = 1/2= sqrt((M_(He))/(M_(SO_2)) (T_(SO_2))/(T_(He)) ) = sqrt(4/64 . (T_(SO_2))/(300))`
`4/64 (T_(SO_2) )/(300) = 1/4, T_(SO_2) = 1200K`
`4/64 (T_(SO_2) )/(300) = 1/4, T_(SO_2) = 1200K`
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