Home
Class 11
CHEMISTRY
The root mean square velocity of an idea...

The root mean square velocity of an ideal gas in a closed container of fixed volume is increased from `5xx10^(4)cms^(-1)` to `10xx10^(4)cm s^(-1)`. Which of the following statements correctly explains how the change is accomplished?

A

By heating the gas, the temperature is doubled

B

By heating the gas, the pressure is quadrupled (i.e. made four times)

C

By heating the gas, the temperature is quadrupled

D

By heating the gas, the pressure is doubled

Text Solution

Verified by Experts

The correct Answer is:
C

`u_1/u_2 = sqrt(T_1/T_2)`
`therefore T_1/T_2 = ((5 xx 10^4)/(10 xx 10^4) )^2 = 1/4`
Promotional Banner

Similar Questions

Explore conceptually related problems

Suppose that we change U_("rms") of gas in a closed container from 5xx10^(-2) cm/sec to 10xx10^(-2) cm/sec, which one of the following might correctly explain how this change was acomplished?

The ratio of final to initial pressures of a gas when u_(rms) of a gas in a container is increased from 5 xx 10^(4) cm sec^(-1)" to " 10 xx 10^(4) cm sec^(-1)

By how many folds the temperature of a gas would increase when the r.m.s. velocity of gas molecules in a closed container of fixed volume is increased from 5 xx 10^(4) cm s^(-1) " to " 10 xx 10^(4) cm s^(-1) ?

Add 6.75xx10^3 cm to 4.52xx10^2 cm.

Two molecules of a gas have speeds of 9xx10^(6) ms^(-1) and 1xx10^(6) ms^(-1) , respectively. What is the root mean square speed of these molecules.

Two molecules of gas have speeds of 9 xx 10^(6) ms^(-1) and 1 xx 10^(6) ms^(-1) respectively. What is the root mean square speed of these molecules?

Calculate the pressure exerted by 10^(23) gas molecules each of mass 10^(-22) g in a container of volume 1 litre the rms speed is 10^(5) cm s^(-1)