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At what temperature, the r.m.s. velocity...

At what temperature, the r.m.s. velocity of a gas measured at `50^(@)C` will become double ?

A

626 K

B

1019 K

C

`200^@C`

D

`1019^@C`

Text Solution

Verified by Experts

The correct Answer is:
D

`C_(rms) = sqrt((3RT)/(M))`
Where T is in kelvin scale.
For rms velocity to be doubled, T in kelvin scale must be raised 4 times. So it should be
`4 xx (50 + 273) = 1292K = 1292 - 273 = 1019^@C`
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