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Pressure exerted by 1 mole of methane in...

Pressure exerted by 1 mole of methane in a 0.25 litre container at 300K using Vander Waal’s equation : (Given : `a = 2.253 "atm" l^(2) "mol"^(-2)` and `b = 0.0428 l "mol"^(-1)`) is

A

82.82 atm

B

152.51 atm

C

190.52 atm

D

70.52 atm

Text Solution

Verified by Experts

The correct Answer is:
A
`(P + (n^2a)/(V^2) )(V - nb) = nRT`
` ( + (2.253)/(0.25 xx 0.25) ) (0.25 - 0.0428) = 0.0821 xx 300`
or ( P + 36.048) (0.2072) = 24.63
`rArr P + 36.048 = 118.87 rArr P = 82.82 atm `
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