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What is the pressure of 2 mole of NH(3) ...

What is the pressure of 2 mole of `NH_(3)` at `27^(@)C` when its volume is 5 lit. in Van der Waal's equation ? `(a = 4.17, b = 0.03711)`

A

10.33 atm

B

9.33 atm

C

9.74 atm

D

9.2 atm

Text Solution

Verified by Experts

The correct Answer is:
B
`(P + (n^2a)/(V^2) ) (V - nb) = nRT`
`(P + ((2)^2 xx 4.17 )/((5)^2) )(5 - 2 xx .03711) = 2 xx .0821 xx 300`
`P = ( 2 xx .0821 xx 300)/(5 - 2 xx .03711) - (4.17 xx 2^2)/(5^2) rArr 10 - 0.66 = 9.33 atm`
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