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The ratio between the root mean square v...

The ratio between the root mean square velocity of `H_2`at 50 K and that of `O_2`at 800 K is

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The correct Answer is:
1
`u_("rms") = sqrt((3RT)/M)`
`(u_(H_(2)))/(u_(O_(2))) = sqrt((T_(H_(2)))/(M_(H_(2))) xx (M_(O_(2)))/(T_(O_(2))))=sqrt(50/2 xx 32/800 ) = 1 `
` :. ` Ratio of mean square velocities , viz , `u_(H_(2))^(2) //u_(O_(2))^(2)=1 `
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