Inside a drum of `V'L a sealed glass tube of volume 25L containing n inert gas at 25 atm pressure is place. The drum is now sealed. During cracket and final pressure inside drum rises to 1.5atm. Find volume of drum [Assume constnat temperature]

Answer

`1187.5`

Explanation

Given that : `P_(1) = 20` atm ,
`V_(1) = 25 L , P_(2) = 1 " atm " , V_(2)=(V-25)L `
`P_(3) = 1.4 " atm " ,V_(3) = V `
Total moles n = moles of air + moles of inert gas
or ` (P_(3)V_(3))/(RT) =(P_(1)V_(1))/(RT) +(P_(2)V_(2))/(RT)`
or `P_(3)V_(3) = P_(1)V_(1)+P_(2)V_(2)`
or `1.4 xx V = 20 xx 25 + 1 xx (V - 25)`
1.4 V = `500 +V - 25`
0.4 V = 475
` rArr V = 1187. 5 L ` .