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2g of a gas X are introduced into an eva...

2g of a gas X are introduced into an evacuated flask kept at `25^(@)C`. The pressure is found to be 1 atm. If 3g of another gas Y are added to the same flask, the total pressure becomes 1.5 atm. Assuming that ideal behaviour, the molecular mass ratio of `M_(x)` and `M_(y)` is

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The correct Answer is:
3
Dalton.s law `P = P_(X) +P_(Y)`
` 1.5 = 1.0 +P_(Y)`
or `P_(Y) = 0.5` atm
For gas X , `P_(X) xx V = 2/(M_(X))RT`
For gas Y , `P_(Y) xx V = 3/(M_(Y))RT`
`(P_(X))/(P_(Y))=2/3 (M_(Y))/(M_(X))`
or `(M_(Y))/(M_(X)) =3/2 xx(P_(X))/(P_(Y)) = (3xx1.0)/(2xx0.5)=3`
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