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For one mole of a van der Waals gas when...

For one mole of a van der Waals gas when `b =0` and `T =30 K` the `PV vs1//V` plot is shown below The value of the van Waals constant a `("atm litre"^(2) mol^(-2))` is
.

A

`1.0`

B

`4.5`

C

`1.5`

D

`3.0`

Text Solution

Verified by Experts

The correct Answer is:
C

`(p+a/(V^(2))) (V)=RT`
`PV +a//V = RT " " rArr PV = RT -a/V`
`y = RT - a(x)`
So slope = a= `(21.6 - 20.1)/(3-2) = (1.5)/1 = 1.5`
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