Home
Class 11
CHEMISTRY
One mole of a monoatomic real gas satis...

One mole of a monoatomic real gas satisfies the equation `p(V-b)=RT` where `b` is a constant. The relationship of interatomic potential `V(r)` and interatomic distance `r` for gas is given by

A

B

C

D

Text Solution

Verified by Experts

The correct Answer is:
C
`P(V-b) =RT`
`rArr PV - Pb = RT`
`rArr (PV)/(RT) = (Pb)/(RT) +1 rArr Z = 1 + (Pb)/(RT)`
Hence `Z gt 1 ` at all pressures . .
This means , repulsive tendencies will be dominant when interatomic distances are small .
This means , interatomic potential is never negative but becomes positive at small interatomic distances .
Promotional Banner

Similar Questions

Explore conceptually related problems

A gas obeys the equation of state P(V-b) =RT (The parameter b is a constnat The slope for an isochore will be .

One mole of a monoatomic ideal gas undergoes a thermodynamic process such that V^3/T^2 = constant. Then,

One mole of a monoatomic ideal gas is expanded by a process described by PV^(3) = C where C is a constant. The heat capacity of the gas during the process is given by (R is the gas constant)

One mole of a monoatomic ideal gas undergoes the process ArarrB in the given P-V diagram. What is the specific heat for this process?

In a process, temperature and volume of one mole of an ideal monoatomic gas are varied according to the relation VT= K, where K is a constant. In this process the temperataure of the gas is increased by DeltaT . The amount of heat absorbed by gas is (R is gas constant).