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In which of the following the oxidation ...

In which of the following the oxidation number of oxygen has been arrangd in increasing order :-

A

`OF_(2) lt KO_(2) lt BaO_(2) lt O_3`

B

`BaO_(2) lt KO_(2) lt O_3 lt OF_2`

C

`BaO_(2) lt O_(2) lt OF_2 lt KO_2`

D

`KO_2 lt OF_2 lt O_3 lt BaO_2`

Text Solution

Verified by Experts

The correct Answer is:
B
Oxidation number of oxygen in `OF_2`
`implies x + (- 2) = 0implies x =+ 2`
Oxidation number of oxygen in `KO_2`
`implies (+1) + 2x = 0 implies x =-1//2`
Oxidation number of oxygen in `BaO_2`
`implies (+2) +2x =0 implies x =-1`
Oxidation number of oxygen in `O_3 = 0`
`:.` Correct order is
`BaO_2 lt KO_2 lt O_3 lt OF_2`
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