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Oxidation number of nitrogen in NaNO(2) ...

Oxidation number of nitrogen in `NaNO_(2)` is

A

`+2`

B

`+3`

C

`+4`

D

`-3`

Text Solution

Verified by Experts

The correct Answer is:
B
Let the oxidation number of N in `NaNO_2` be x
`+1 +x+(-2)xx2 =0`
`1+x -4 =0 , x=+3`
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