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The oxidation number of oxygen in KO3,Na...

The oxidation number of oxygen in `KO_3,Na_2O_2` is

A

`3,2`

B

`1,0`

C

`0,1`

D

`-0.33,-1`

Text Solution

Verified by Experts

The correct Answer is:
D
Let oxidation number of oxygen = x
O.N of oxygen in `KO_3 =1 + 3x =0`
`:. X = -1//3 = -0.33`
O.N of oxygen in `Na_2O_2 = 2 xx 1 + 2x =0`
`:. X = -1`
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