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The oxidation number of sulphur in H2S2O...

The oxidation number of sulphur in `H_2S_2O_8 , H_2S_2O_4 , H_2S_2O_6` are respectively

A

`+ 3, + 4, + 5`

B

`+ 5, + 4, + 3`

C

`+ 6, + 3, + 5`

D

`+ 3, + 5, + 4`

Text Solution

Verified by Experts

The correct Answer is:
C
`H-O-underset(O)underset(||)overset(O)overset(||)S-O-O-underset(O)underset(||)overset(O)overset(||)S-O-H " "(H_2S_2O_8)`
Each sulphur is connected to oxygen atom by 2 double bonds and 2 single bonds. So oxidation number of `S = 2xx (+2) + 2xx (+1) =+ 6`
`H-O-underset(x)overset(O)overset(||)S-underset(x)overset(O)overset(||)S-O-H" "(H_2S_2O_4)`
`implies x =+2 +1 + 0 =+3`
`H-O-underset(O)underset(||)overset(O)overset(||)(S_x)-underset(O)underset(||)overset(O)overset(||)(S_x)-O-H" "(H_2S_2O_6)`
`implies x = + 1 + 2(+2) +0 =+5`
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