In which of the following compounds, an element exhibits two different oxidation states?

Options

A. `NH_2 OH`
B. `NH_4 NO_3`
C. `N_2H_4`
D. `N_3H`

Answer

B

Explanation

`NH_4NO_3` is actually `NH_(4)^(+)` and `NO_(3)^(-)` it is an ionic compound.
The oxidation number of nitrogen in the two species is different as shown below
Let, oxidation number of N in `overset(+)(NH_4)` is x.
`implies x + (4 xx1) =+1`
or `x+4 =+1 " or " x =-3`
Let, oxidation number of N in `NO_3^(-)` is x
`implies x +(3 xx -2) =-1` or `x - 6 =-1 ` or `x = + 5`