Home
Class 11
CHEMISTRY
The oxidation states of S atoms in S4O6^...

The oxidation states of S atoms in `S_4O_6^(2-)` from left to right respectively are

A

`+ 6, 0, 0, +6`

B

`+3, +1, +1, +3`

C

`+5, 0, 0, +5`

D

`+4, +1, +1, +4`

Text Solution

Verified by Experts

The correct Answer is:
C
Left S atom : +2 each from = O +4
`{:(+1 "from" - O^(-),+1),("0 from – S",0/(+5)):}`
Promotional Banner

Similar Questions

Explore conceptually related problems

The oxidation states of S atom in S_(4)O_(6)O^(2-) from left to right respectively are O-underset(O)underset(||)overset(O)overset(||)S-S-S-underset(O)underset(||)overset(O)overset(||)S-O

The oxidation states of S atoms in S_(2)O_(6)^(2-) from left to right respectively are {:(" O O"),(" || ||"),(bar(O)-S-S-S-S-bar(O)),(" || ||"),(" O O"):}

The oxidation state of O-atom is +2 in

The oxidation states of S in S_2O_8^(2-) is