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H2O2 oxidises K4Fe(CN)6...

`H_2O_2` oxidises `K_4Fe(CN)_6`

A

In neutral solution

B

In acidic solution

C

In non-polar solvent

D

In alkaline solution

Text Solution

Verified by Experts

The correct Answer is:
B
`H_2O_2` oxidize `K_4 [Fe(CN)_6]` in acidic solution to `K_3[Fe(CN)_6]` and reduce to `H_2O.`
`2K_4[overset(+2)(Fe)(CN)_6]+H_2SO_4+overset(-1)(H_2O_2)rarr2K_3[overset(+3)(Fe)(CN)_6]\+K_2SO_4+2H_2overset(-2)O`
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