Home
Class 11
CHEMISTRY
Maximum number of moles of electrons tak...

Maximum number of moles of electrons taken up by one mole of `NO_(3)^(-)` when it is reduced to :

A

`NH_3`

B

`NH_2OH`

C

NO

D

`NO_2`

Text Solution

Verified by Experts

The correct Answer is:
A
Oxidation no. of N in `NO_3^(-) =+5`
`NH_3=-3 , NH_2 OH =-1 , NO =+2 , NO_2 =+4`
So one mole of `NO_3^(-)` will require maximum no. of moles of electron by reducing into `NH_3{5-(-3)=8}`
Promotional Banner

Similar Questions

Explore conceptually related problems

Number of moles of electrons take up when 1 mole of NO_(3)^(-) ions is reduced to 1 mole of NH_(2)OH is:

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) ion is:

The number of mole of oxalate ions oxidised by one mole of MnO_(4)^(-) is :

Number of moles of K_2Cr_2O_7 reduced by one mole of Sn^(2+) ion is

The mass of one mole of electron is

Total number of moles of HlO_(4) required by one mole of D-glucose when it is subjected to periodic acid oxidation is

Number of moles of electrons are needed to convent one mole of nitrate ion to hydrazine are "

The no of electrons present in one mole of Azide ion are (N_(3)^(-))