Home
Class 11
CHEMISTRY
The values of n in the following equatio...

The values of n in the following equation is
`Cr_(2)O_(7)^(2-) + 14H^(+) + nFe^(2+) to 2Cr^(3-) + nFe^(3+) + 7H_(2)O`

A

2

B

3

C

6

D

7

Text Solution

Verified by Experts

The correct Answer is:
C
`Cr_(2)O_(7)^(2-)+14H^(+)+nFe^(2+) rarr2Cr^(3+)+nFe^(3+)+7H_2O`
On balancing the charge on both sides `-2 + 14 + 2n =+6 + 3n`
`n=6`
Promotional Banner

Similar Questions

Explore conceptually related problems

Balance the following equation stepwise: Cr_(2)O_(7)^(2-) + Fe^(2+)++H^(o+)rarrCr^(3+) + Fe^(3+) + H_(2)O

The equivalent mass of HCl in the following reaction : K_(2)Cr_(2)O_(7) + 14HCl to 2KCl + 2CrCl_(3) + 3Cl_(2) + 7H_(2)O would be

What is the value of x in the following equation. Cr_2O_7^(2-)+8H^(o+)+xS_2O_3^(2-)to2Cr^(3+)+3SO_4^(2-)+3S+4H_2O

In the following reaction 2I- + Cr_(2)O_(7)^(2-)+14H^(+) rarr I_(2)+2Cl^(3)+7H_(2)O Unbalanced parts are