The number of electrons lost in the following change is
`Fe+H_(2)OrarrFe_(3)O_(4)+H_(2)`

Answer

8

Explanation

`Fe_(3)O_(4)-=FeO+Fe_(2)O_(3)`
Therefore, the change can be represented as
`FerarrFe^(2+)+2e^(-), 2Ferarr2Fe^(3+)+6e^(-)`
`therefore` Number of electrons transferred = 8.