Home
Class 11
CHEMISTRY
12.53 cm^(3) of 0.51 M SeO(2) reacts ex...

12.53 `cm^(3)` of 0.51 M `SeO_(2)` reacts exactly with 25.5 `cm^(3)` of 0.1 M `CrSO_(4)` which is oxidised `Cr(SO_(4))_(3)` To what oxidation state is the selenium converted during the reaction ?

Text Solution

Verified by Experts

The correct Answer is:
0
Let O.N. Of Se in the new compound = x

Now `12.53cm^(3)` of 0.051M `SeO_(2)=12.53xx0.051=0.64` millimoles of `SeO_(2)` and `25.5cm^(3)` of 0.1 `M CrSO_(4)=25.5xx0.1=2.55` millimoles of `CrSO_(4)` But according to balanced redox equation, `(4-x)` moles of `CrSO_(4)` reduce 1 mole of `SeO_(2)`
`therefore` 2.55 millimoles of `CrSO_(4)` will reduce
`SeO_(2)=(2.55)/((4-x))` millimoles
But `SeO_(2)` actually reduced = 0.64 millimoles
Equating these two values, we have,
`(2.55)/(4-x)=0.64`
or x = 0.
Promotional Banner

Similar Questions

Explore conceptually related problems

A volume of 12.5 mL of 0.05 M SeO_(2) reacts with 25 mL of 0.1 M CrSO_(4) which is oxidised to Cr^(3+) . To what oxidation state was the selenium converted by the reaction ?

12.53 mL of 0.0509MSeO_(2) reacted with 25.52 mL 0.1M CrSO_(4) solution. In the raeaction Cr^(2+) was oxidised to Cr^(3+) . To what oxidation state selenium was converted in the reaction? Write the redox change for SeO_(2) .

15.0 mL of 0.05 M SeO_2 reacts with 30.6 mL of 0.1 M CrSO_4 solution . If during the reaction CrSO_4 gets oxidised to Cr_2(SO_4)_3 to what oxidation state does selenium get converted ?

200 cm^(3) of 0.1 M H_(2)SO_(4) is mixed with 150 cm^(3) of 0.2M KOH. Find the value of evolved heat.

When 50 cm^(3) of 0.2 N H_(2)SO_(4) is mixed with 50 cm^(3) of 1 N KOH , the heat liberated is

2.5 cm^(3) of 0.2 M H_(2)SO_(4) solution is diluted to 0.5 dm^(3) . Find normality of the diluted solution .

In an experiment, 50 mL of 0.1 M solution off a metallic salt M(NO_(3)) reacted exactly with 25 mL of 0.1 M solution of NaSO_(3) in the reaction SO_(3)^(2-) is oxidized to SO_(4)^(2-) . If in the original salt oxidation number fo the metal was 3, what would be the new oxidation number of metal?