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The volume of oxygen liberated from 15 m...

The volume of oxygen liberated from `15 ml` of 20 volume `H_(2)O_(2)` is

A

250 mL

B

300 mL

C

150 mL

D

200 mL

Text Solution

Verified by Experts

The correct Answer is:
B
20 vol. `H_2O_2` means that 1mL of this `H_2O_2` will release 20mL `O_2` at STP . Therefore decomposition of 15mL of 20 vol. `H_2O_2` will give `15xx 20 ` = 300mL `O_2` .
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