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HOCl+H2O2rarrH3O^++Cl^(-)+O2 I2+H2O2+2...

`HOCl+H_2O_2rarrH_3O^++Cl^(-)+O_2`
`I_2+H_2O_2+2OH^(-)rarr2I^(-)+2H_2O+O_2`
Choose the correct option

A

An oxidising agent in both (i) and (ii)

B

An oxidising agent in (i) and reducing agent in (ii)

C

A reducing agent in (i) and oxidising agent in (ii)

D

A reducing agent in both (i) and (ii)

Text Solution

Verified by Experts

The correct Answer is:
B


Thus, here `H_2O_2` oxidises HI into `I_2` hence, it behaves as oxidising agent

Here,` H_2O_2` reduces HOCl to `Cl^(-1)` , thus, it acts as reducing agent.
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