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The oxide that gives H2 O2 on treatment ...

The oxide that gives `H_2 O_2` on treatment with dilute `H_2 SO_4` is

A

`PbO_2`

B

`BaO_(2).8H_(2)O+O_2`

C

`MnO_2`

D

`TiO_2`

Text Solution

Verified by Experts

The correct Answer is:
B
Oxides such as `BaO_2, Na_2O_2` etc, which contain peroxide linkage (i.e., `O - O ` or `O_(2)^(2-)` ) on treatment with dilute `H_2SO_4` give `H_2O_2` but dioxides (O = M = O, where M is the metal atom) such as `PbO_2, MnO_2, TiO_2` do not give `H_2O_2` on treatment with dilute `H_2SO_4` .
`underset("peroxide")underset("Hydrated barium")(BaO_2 .8H_2O(s))+H_2SO_4(aq)rarrBaSO_4(s)+underset("peroxide")underset("Hydrogen")(H_2O_2(aq))+8H_2O(l)`
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