Calculate the volume of `10` volume `H_(2)O_(2)` solution that will react with `200 mL of 2N KMnO_(4)` in acidic medium.

Answer

224

Explanation

Normality of 10 volumes `H_(2)O_(2)`
`= ("Volume strength")/5.6 == 10/5.6 = N`
Applying normality equation,
`N_(1)V_(1) (H_(2)O_(2)) = N_(2)V_(2)(KMnO_(4))`
`=10/5.6 xx V_(1) = 2 xx 200` or `V_(1) = (2 xx 200 xx 5.6)/10 = 224` mL