The volume strength of `1*5` N `H_(2)O_(2)` solution is

Answer

8.4

Explanation

Strength = Normality `xx` Eq. Mass = `1.5 xx 17`
`=25.5 gL^(-1)`
`underset(68 g = 68 mL)(2H_(2)O_(2)) to 2H_(2)O + underset("22400 mL")O_(2)`
`O_(2) = 22400` mL
25.5 g of `H_(2)O_(2)` on decomposition gives `O_(2) = (22400 xx 25.5)/68 = 8400` mL
`therefore 1000 mL` of `H_(2)O_(2)` solution gives 8400 mL of `O_(2)`
1mL of `H_(2)O_(2)` solution gives 8.4 mL of `O_(2)`
`therefore` Vol. strength of `H_(2)O_(2) = 8.4`