The amount of anhydrous Na2 CO3 present ...

The amount of anhydrous `Na_2 CO_3` present in 250 ml of 0.25 M solution is

A

6.225 g

B

66.25 g

C

6.0 g

D

6.625 g

Verified by Experts

The correct Answer is:

D

`M=(w)/(mxxV(l)),0.25=(w)/(106xx0.25)`
w = 6.625 g.

Similar Questions

Explore conceptually related problems

Calculate the mass of anhydrous Na_2CO_3 required to prepare 250 ml 0.25 M solution .

The amount of H_2SO_4 present in 400 mL of 0.1 M solution of the acid is -

How many grams of NaOH are present in 250 mL of 0.5 M NaOH solution?

How many moles and how many grams of HCI are present in 250 ml of 0.5 M HCl solution?

The weight of AgNO_(3) (Mol.wt = 170) present in 100 ml of 0.25 M solution in - grams

How many Na^+ ions are present in 100 mL of 0.25 M of NaCl solution ?

What is the weight ( in g) of Na_(2) CO_(3) molar mass = 106 ) present in 250 mL of Its 0.2 M solution ?