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6.02 xx 10^(20) molecules of urea are pr...

`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is
(Avogadro constant, `N_(A) = 6.02 xx 10^(23)mol^(-1))`

A

`0.02M`

B

`0.01M`

C

`0.001M`

D

`0.1M`

Text Solution

Verified by Experts

The correct Answer is:
B
Mole of urea = `(6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` moles
Conc. Of solution (in molarity) `=(10^(-3))/(100)xx1000=0.01M`.
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