The molarity of a solution obtained by mixing 800 mL of 0.5 M HCl with 200 mL of 1 M HCl will be

Options

A. 0.8 M
B. 0.6 M
C. 0.4 M
D. 0.2 M

Answer

B

Explanation

`underset("(Initial)")(M_(1)V_(1))+M_(2)V_(2)=underset("(Final)")(M_(3)V_(3))`
`V_(3)=V_(1)+V_(2)=800+200=1000`
`M_(3)xx1000=0.5xx800+1xx200,M_(3)=(600)/(1000)=0.6M`.