Home
Class 12
CHEMISTRY
If the concentration of glucose (C(6)H(1...

If the concentration of glucose `(C_(6)H_(12)O_(6))` in blood is `0.9 "g L"^(-1)`, what will be the molarity of glucose in blood ?

A

5 M

B

50 M

C

0.005 M

D

0.5 M

Text Solution

Verified by Experts

The correct Answer is:
C
In the given question, `0.9gL^(-1)` means that 1000 mL (or 1L) solution contains 0.9 g of glucose.
`therefore` Number of moles = 0.9 g glucose = `(0.9)/(180)` mol glucose
`=5xx10^(-3)` mol glucose
(where, molecular mass of glucose `(C_(6)H_(12)O_(6))=12xx6+12xx1+6xx16=180u`)
i.e., 1L solution contains 0.005 mole glucose or the molarity of glucose is 0.005 M.
Promotional Banner

Similar Questions

Explore conceptually related problems

If the concentration of glucose (C_(6)H_(12)O_(6)) in blood is 0.72 gL^(-1) , the molarity of glucose in blood is _____ xx 10^(-3)M . (Nearest integer) [Given: Atomic mass of C=12, H=1, O=16u]

360 amu of Glucose (C_6H_12O_6) contains :

A solution of glucose (C_(6)H_(12)O_(6)) in water is labelled as 10% by weight . What would be the molality of the solution ?

If concentration of glucose in blood is 0.72 gL^(-1) . The molarity of glucose is:

A solution is 0.150 mole fraction glucose (C_(6)H_(12)O_(6)) and 0.850 mole fraction water (H_(2)O) . The molality of glucose in the solution is

Calculate the molecular mass of glucose (C_(6)H_(12)O_(6)) molecule in amu.