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35.4 mL of HCl is required for the neutr...

35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid is

A

0.97 N

B

0.142 N

C

0.194 N

D

0.244 N

Text Solution

Verified by Experts

The correct Answer is:
C
We know that 1g equivalent weight of
NaOH = 40 g
`therefore` 40 g of NaOH = 1 g eq. Of NaOH
`therefore` 0.275 g of NaOH = `(1)/(40)xx0.275` eq.
`=(1)/(40)xx0.275xx1000=6.88` meq.
`therefore underset((HCl))(N_(1)V_(1))=underset((NaOH))(N_(2)V_(2))`
`N_(1)xx35.4=6.88` (`because` meq = NV)
`N_(1)=0.194`.
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