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Calculate the molality of 1 litre soluti...

Calculate the molality of 1 litre solution of 93% `H_(2)SO_(4) ("weight"//"volume")`. The density of solution is 1.84 g `mL^(-1)`.

A

10.43

B

20.36

C

12.05

D

14.05

Text Solution

Verified by Experts

The correct Answer is:
A
Molarity `(M)=("Percent of solute"xx10)/("Mol. wt. of solute")`
`=(93xx10)/(98)=9.48`
`therefore` Molality `(m)=(M)/(D-(Mxxw)/(1000))=(9.48)/(1.84-(9.48xx98)/(1000))`
= 10.43.
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