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25 g of a solute of molar mass 250 g mol...

25 g of a solute of molar mass `250 g mol^(-1)` is dissolved in 100 ml of water to obtain a solution whose density is `1.25 g ml^(-1)`. The molarity and molality of the solution are respectively

A

0.75 and 1

B

0.8 and 1

C

1 and 0.8

D

1 and 0.75

Text Solution

Verified by Experts

The correct Answer is:
C
No. Of moles of solute = `(25)/(250)=0.1` moles
Molarlity = `("No. Of moles of solute")/("Volume of solvent in litre")=(0.1)/((100)/(1000))=1M`
Molality = `("no. Of moles of solute")/("mass of solvent in kg")`
Mass `=d xx V`
`=1.25xx100=125g`
Molality = `(0.1)/(125//1000)=0.8m`.
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