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The density of 3M solution of NaCl is 1....

The density of `3M` solution of `NaCl` is `1.25 g mL^(-1)`. The molality of the solution is

A

2.79

B

1.79

C

0.79

D

2.98

Text Solution

Verified by Experts

The correct Answer is:
A
Molarity = 3M
3 moles of solute present in 1 litre of solution.
`d=(m)/(v)`
Mass of solution = density of solution `xx` volume of solution.
`m=1.25xx1000`
`m=1250g`.
Mass of solvent = mass of solution – mass of solute
`=1250-3xx58.5`
= 1074.50
Molality of solution, `m=(n_("soluble"))/(W_("solvent"(g)))xx1000`
`=(3)/(1074.50)xx1000`
= 2.79 m.
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