Home
Class 12
CHEMISTRY
The weight percent of sucrose (formula w...

The weight percent of sucrose (formula weight = 342 g `"mol"^(-1)` in an aqueous solution is 3.42. The density of the solution is 1 g `mL^(-1)`, the concentration of sucrose in the solution in mol `L^(-1)` is

A

`0.01`

B

`0.1`

C

`1.0`

D

10

Text Solution

Verified by Experts

The correct Answer is:
B

3.42 g sucrose in 100 g solution
d = 1g / mL
`therefore d = ("Mass")/("Volume")`
Volume = `(100)/(1)=100mL`
Molarity = `(n)/(v)xx1000`
Molarity = `(3.42)/(342xx100)xx1000=0.1`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

What osmotic pressure would 1.25 molal sucrose solution exhibit at 25^(@)C ? The density of the solution is 1.34 g//ml

The density of 2M solution of acetic acid (Mol. Wt. 60) is 1.02 g ml^(-1) . The molality of the solution 'X' is

The density of 2.0 M solution of a solute is 1.2 g mL^(-1) . If the molecular mass of the solute is 100 g mol^(-1) , then the molality of the solution is

The mole fraction of urea in an aqueous urea solution containing 900 g of water is 0.05. If the density of the solution is 1.2 g cm^(-3) , the molarity of urea solution is __________ Given data: Molar masses of urea and water are 60 g "mol"^(-1) and 18 g "mol"^(-1) , respectively)

An aqueous solution of 0.1 molal concentration of sucrose should have freezing point (K_(f)=1.86K mol^(-1)kg)

Dissolving 120g of urea (mol wt 60) in 100 g of water gave solution of density 1.158g//mL . The molarity of the solution is