Home
Class 12
CHEMISTRY
At 300 K , when a solute is aded to a...

At 300 K , when a solute is aded to a solvent ,its vapour pressure over mercury reduces from 50 mm to 45 mm . The value of mole fraction of solute wil be _____.

A

`0.005`

B

`0.010`

C

`0.100`

D

`0.900`

Text Solution

Verified by Experts

The correct Answer is:
C

Vapour pressure of solvent `P_(0)=50mm`
Vapour pressure of solution P = 45mm
Mole fraction of solute `=(P_(0)-P)/(P_(0))=(50-45)/(50)`
`=(5)/(50)=0.1`.
Promotional Banner

Similar Questions

Explore conceptually related problems

When 45 grams of a solute is added to 900 gm of water, its vapour pressure decreased from 30 mm to 24 mm. The mole fraction of the solvent in the solution is

When 5 grams of a solute is added to 90gm of water,its vapour pressure decreased from 30mm to 27mm . The mole fraction of the solvent in the solution is

The vapour pressure of a dilute aqueous solution of glucose is 750 mm of mercury at 373 K . The mole fraction of solute is :

The vapour pressure of pure liquid solvent 0.50 atm. When a non-volatile solute B is added to the solvent, its vapour pressure drops to 0.30 atm. Thus, mole fraction of the component B is

The vapour pressure of a dilute aqueous solution of glucose is 740 mm of mercury at 373 K. The mole fraction of the solute is:

On adding solute to a solvent having vapour pressure 0.80atm ,vapour pressure reduces to 0.60atm .Mole fraction of solute is

Vapour pressure of dilute solution of glucose is 750m of mercury at 373K. The mole fraction of solute is