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The vapour pressure of benzene at a cert...

The vapour pressure of benzene at a certain temperature is `640 mm` of Hg A non-volatile and non-electrolyte solid weighing `2.175g` is added to `39.08g` of benzene .the vapour pressure of the solution is `600 mm` of Hg. What is the molecular weight of solid substance ?

A

`49.50`

B

`59.0`

C

`69.5`

D

`79.8`

Text Solution

Verified by Experts

The correct Answer is:
C
`(P^(o)-P_(s))/(P^(o))=((w)/(m))/((w)/(m)+(W)/(M))because(W)/(M)gt(w)/(m)implies(640-600)/(640)`
`=(w)/(m)xx(M)/(W)implies(40)/(640)=(2.175xx78)/(mxx39.08),m=(2.175xx78)/(39.08)xx(640)/(40)`
`m=69.45`.
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