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6g of urea ( molecular weight =60) was d...

`6g` of urea ( molecular weight `=60)` was dissolved in `9.9` moles of water. If the vapour pressure of pure water is `P^(@)`, the vapour pressure of solution is `:`

A

`0.10 P_(o)`

B

`1.10 P_(o)`

C

`0.90 P_(o)`

D

`0.99 P_(o)`

Text Solution

Verified by Experts

The correct Answer is:
C
`(P^(o)-P_(s))/(P^(o))=(n)/(N)implies(P^(o)-P_(s))/(P^(o))=(1)/(9.9)implies9.9P^(o)-9.9P_(s)=P^(o)`
`8.9P^(o)=9.9P_(s)impliesP_(s)=(8.9)/(9.9)P^(o)~~0.90P^(o)`
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