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The mass of a non-volatile solute of mol...

The mass of a non-volatile solute of molar mass `40g" "mol^(-1)` that should be dissolved in 114 g of octane to lower its vapour pressure by 20% is

A

10 g

B

11.4 g

C

9.8 g

D

12.8 g

Text Solution

Verified by Experts

The correct Answer is:
A
`(P_(0)-P_(s))/(P_(0))=(20)/(100)`
`(20)/(100)=(w//40)/(114//114+w//40)`
`w=10g`.
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