A solution has `1:4` mole ratio of pentane to hexane . The vapour pressure of pure hydrocarbons at `20^@C`are `440` mmHgfor pentane and `120`mmHg for hexane .The mole

Options

A. `0.549`
B. `0.200`
C. `0.786`
D. `0.478`

Answer

D

Explanation

`P_(T)=p_(p)^(o)x_(p)+p_(h)^(o)x_(h)=440xx(1)/(5)+120xx(4)/(5)`
`=88+96=184, p_(p)^(o)x_(p)=y_(p)P_(T),(88)/(184)=y_(p)`
`y_(p)=0.478`