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The mass of glucose that would be dissol...

The mass of glucose that would be dissolved in 50g of water in order to produce the same lowering of vapour pressure as is produced by dissolving 1g of urea in the same quantity of water is :

A

1 g

B

3 g

C

6 g

D

18 g

Text Solution

Verified by Experts

The correct Answer is:
B
`(P^(o)-P_(s))/(P_(s))=(w_(1)M_(2))/(w_(2)M_(1))`
To produce same lowering of vapour pressure `((P^(o)-P_(s))/(P_(s)))` term will be same for both the cases (solvent is same)
`therefore (w_(g)xx18)/(50xx180)=(w_(u)xx18)/(50xx60)`
(`w_(g)` = weight of glucose, `w_(u)` = weight of urea)
or, `(w_(g)xx18)/(50xx180)=(1xx18)/(50xx60)or,w_(g)=3`.
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