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What is the osmotic pressure of a 0.0020...

What is the osmotic pressure of a `0.0020` mol `dm^(-3)` sucrose `(C_(12)H_(22)O_(11))` solution at `20^(@)C`? (Molar mass contant, `R = 8.314 JK^(-1) mol^(-1). 1 dm^(3) = 0.001 m^(3))`

A

4870 Pa

B

4.87 Pa

C

0.00487 Pa

D

0.33 Pa

Text Solution

Verified by Experts

The correct Answer is:
A
`pi=CRT`
`C=.002mol dm^(-3)=.002 molL^(-1)`
`R=8.314JK^(-1) mol^(-1)`
(if pressure in k Pascals)
T implies 20 + 273 = 293 K
So, `pi=.002xx8.314xx293`
`=4.8720kPa=4872.0Pa`.
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