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If 0.5 g of a solute (molar mass 100 g m...

If 0.5 g of a solute (molar mass 100 g `mol^(-1)`) in 25 g of solvent elevates the boiling point by 1 K, the molal boiling point constant of the solvent is

A

2

B

8

C

5

D

`0.5`

Text Solution

Verified by Experts

The correct Answer is:
C
`K_(b)=(DeltaT_(b)xxm_(B)xxw_(A))/(w_(B)xx1000)`
`K_(b)=(1xx100xx25)/(0.5xx1000)=5.00`
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