The unit of ebullioscopic constant is

Options

A. `K kg mol^(-1) or K ("molality")^(-1)`
B. `mol kg K^(-1) or K^(-1)` (molality)
C. `kg mol^(-1)K^(-1)orK^(-1)("molality")^(-1)`
D. `Kmol kg^(-1)` or K (molality)

Answer

A

Explanation

As we know from elevation in boiling point that
`DeltaT_(b)=K_(b)m`
`K_(b)=(DeltaT_(b))/(m)`
Unit of `K_(b)=("unit of "DeltaT_(b))/("unit of m")=("K")/("molality")`
`implies (K)/(mol kg^(-1))=Kmol^(-1)kg`.