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The molar freezing point constant for wa...

The molar freezing point constant for water is `1.86 ^@C`/ molal . If 342 gm of canesugar `(C_(12)H_(22)O_(11))` are dissolved in 1000 gm of water, the solution will freeze at

A

`-1.86^(@)C`

B

`1.86^(@)C`

C

`-3.92&(@)C`

D

`2.42^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
A
`DeltaT_(f)=1.86xx((342)/(342))=1.86^(@), therefore T_(f)=-1.86^(@)C`.
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