Home
Class 12
CHEMISTRY
A 0.1 molal aqueous solution of a weak a...

A `0.1` molal aqueous solution of a weak acid is `30%` ionized. If `K_(f)` for water is `1.86^(@)C//m`, the freezing point of the solution will be.

A

`-0.36^(@)C`

B

`-0.24^(@)C`

C

`-0.18^(@)C`

D

`-0.54^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
B

`DeltaT_(f)=iK_(f)m`
`HArarrH^(+)+A^(-)`
`1-alpha alpha alpha`
`1-0.3 0.3 0.3`
`i=1-0.3+0.3+0.3`
`i=1.3`
`DeltaT_(f)=1.3xx1.86xx0.1=0.2418`
`T_(f)=0-0.2418=-0.2418^(@)C`
Promotional Banner

Similar Questions

Explore conceptually related problems

0.5 molal aqueous solution of a weak acid (HX) is 20% ionised. If K_(f) for water is 1.86K kg mol^(-1) , the lowering in freezing point of the solution is

0.5 molar aqueous solution of a weak acid (HX) is 20% ionised. If K_(f) for water is 1.86 K kg mol^(-1) , the lowering in freezing point of the solution is

In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3. Taking K_(f) for water as 1.85, the freezing point of the solution will be nearest to

In a 0.2 molal aqueous solution of a weak acid HX the degree of ionization is 0.3 . Taking k_(f) for water as 1.85 the freezing point of the solution will be nearest to-

If 0.2 molal aqueous solution of a weak acid (HA) is 40% ionised then the freezing point of the solution will be ( K_f for water = 1.86^@ C