Heavy water freezes at

Options

A. `0^(@)C`
B. `3.8^(@)C`
C. `38^(@)C`
D. `-0.38^(@)C`

Answer

B

Explanation

Since the solid ice is a regular pattern of molecules, small amounts of solute break up the pattern. So the solute increases the chemical potential of the liquid water, or lowers the freezing point.
Since the solid ice is a regular pattern of molecules, small amounts of solute break up the pattern. So the solute increases the chemical potential of the liquid water, or lowers the freezing point. If some molecules fit into the ice structure even better than ordinary water, then it will lower the chemical potential of the water or increases the freezing point.
Due to stronger hydrogen bonding in `D_(2)O`, the addition of heavy water to normal water increases the freezing point of pure water. We can say that pure heavy water has higher freezing point than normal water. Although the difference can not be very high.