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In equimolar solution of glucose, NaCl a...

In equimolar solution of glucose, NaCl and `BaCl_(2)` , the order of osmotic pressure at same temperature is as follow `:`

A

Glucose `gt` NaCl `gt BaCl_(2)`

B

NaCl `gt BaCl_(2) gt` Glucose

C

`BaCl_(2) gt` NaCl `gt` Glucose

D

Glucose `gt BaCl_(2) gt` NaCl

Text Solution

Verified by Experts

The correct Answer is:
C
`BaCl_(2)=Ba^(2+)+2Cl^(-)=3` ion
`NaClimpliesNa^(+)+Cl^(-)=2` ion
Glucose implies No ionisation
`therefore BaCl_(2)gtNaClgt` Glucose
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