The elevation in boiling point expected for 0.3 m `Al_(2)(SO_(4))_(3)` solution will be how many times compared with the elevation in boiling point of 0.1 m `Na_(2)SO_(4)` solution ?

Answer

5

Explanation

`DeltaT_b=iK_bxxm`
For 0.3 m `Al_2(SO_4)_3 , DeltaT_b=5xxK_bxx0.3 = 1.5 K_b`
For 0.1 m `Na_2SO_4, DeltaT_b = 3xx K_b xx0.1=0.3K_b`
Thus, `DeltaT_b` for `Al_2(SO_4)_3` solution will be 5 times that for `Na_2SO_4` Solution.